Mathematics Practice Test

The correct answer is (d) Reflexive. The given equation is a form of the reflexive property a = a, where each side of the equation equals itself. The commutative and associative properties rearrange the numbers, and the distributive property multiplies numbers across sums or differences.

The correct answer is (c) 5%. Using the formula I = PRT, we rearrange to get R = I / (PT). Thus, R = ?80 / (?2,400 * 8/12) => 5%.

This question tests the understanding of how to calculate an average (arithmetic mean). The average is found by summing all values and dividing by the number of values. In this case, we sum A, B, and C, then divide by 3 (as there are three values). This corresponds to option c: (A+B+C)/3.

To find the interest rate, we use the formula: Interest = Principal * Rate * Time <br> 750 = 15000 * R * 1

Let's use the compound interest formula: A = P(1 + r)^t <br> Where A is final amount, P is principal, r is annual rate, t is time in years. <br> A = 5000(1 + 0.12)^2 = 5000(1.2544) = 6,272 <br> The closest answer is P6,200.

To convert 0.0125 to a fraction, we multiply both numerator and denominator by 10,000 to remove the decimal: 0.0125 = 125/10000. Now we need to reduce this fraction to its lowest terms by dividing both numerator and denominator by their greatest common divisor (GCD). The GCD of 125 and 10000 is 125. 125/125 = 1 and 10000/125 = 80. Therefore, 0.0125 = 1/80 in its lowest terms.

Given that 3ab = 15 and b = 5, we can substitute b with 5: 3a(5) = 15. Simplifying: 15a = 15. Dividing both sides by 15: a = 1. Therefore, the correct answer is 1.

Using the simple interest formula: I = P * r * t, where I = 1,200, r = 6% = 0.06, t = 1 year, and we need to solve for P. Substituting: 1,200 = P * 0.06 * 1. Solving for P: P = 1,200 / 0.06 = 20,000. Therefore, the correct answer is P20,000.

Calculating each power and adding them gives \(1 + 823543 + 16384 + 1 + 823543 + 128 + 78125 = 1,741,725\). Each component corresponds to the digits 1, 7, 4, 1, 7, 2, 5 raised to the seventh power.